165 lines
4 KiB
C++
165 lines
4 KiB
C++
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// Copyright (c) 1999 Microsoft Corporation. All rights reserved.
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//
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// Implementation of ExprBlock.
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//
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#include "stdinc.h"
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#include "engexpr.h"
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HRESULT
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Expression::Generate()
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{
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HRESULT hr = InfixToPostfix();
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if (FAILED(hr))
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{
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// clean up the working stack
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while (!m_stack.empty())
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m_stack.pop();
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return hr;
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}
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return S_OK;
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}
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int Precedence(Token t)
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{
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switch(t)
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{
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case TOKEN_op_pow: return 10;
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case TOKEN_sub: return 9; // unary - (negation)
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case TOKEN_op_mult: return 8;
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case TOKEN_op_div: return 7;
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case TOKEN_op_mod: return 6;
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case TOKEN_op_plus:
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case TOKEN_op_minus: return 5;
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case TOKEN_op_lt:
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case TOKEN_op_leq:
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case TOKEN_op_gt:
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case TOKEN_op_geq:
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case TOKEN_op_eq:
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case TOKEN_op_neq:
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case TOKEN_is: return 4;
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case TOKEN_op_not: return 3;
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case TOKEN_and: return 2;
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case TOKEN_or: return 1;
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case TOKEN_lparen: return 0;
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default:
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assert(false);
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return 12;
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}
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}
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// Infix to postfix conversion is performed by a single scan of the infix expression blocks.
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// A stack is used to hold some of the blocks before they eventually are appended to the postfix expression.
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//
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// The algorithm follows the following rules:
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// * If the current item is an value it is immediately appended.
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// * If the current item is an operator, pop and append each operator on the stack until one is encountered that:
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// - has lower precedence than the current operator OR
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// - is a left paren OR
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// - is a unary operator and the current item is also unary
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// Once done with this popping, push the current item onto the stack.
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// * If the current item is a left paren, push it onto the stack.
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// * If the current item is a right paren, pop and append all the operators until the matching left paren is found.
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// Discard the left and right paren as parens are not needed in postfix.
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// * After scanning all items of the input, pop and append any operators that remain on the stack.
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//
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// Before working with this code, try out a few expressions on paper to see how this works.
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HRESULT
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Expression::InfixToPostfix()
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{
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assert(m_stack.empty());
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HRESULT hr = S_OK;
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ExprBlocks::index iLast = m_e.Next();
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assert(iLast > 0);
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for (ExprBlocks::index i = 0; i < iLast; ++i)
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{
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const ExprBlock &b = m_e[i];
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if (b.k == ExprBlock::_val || b.k == ExprBlock::_call)
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{
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// this is an operand -- send it directly to the postfix output
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hr = m_eblocks.Add(b);
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if (FAILED(hr))
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return hr;
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}
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else
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{
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if (b.op == TOKEN_rparen)
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{
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// pop whatever's left until the matching lparen
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for (;;)
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{
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if (m_stack.empty())
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{
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assert(false);
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return E_FAIL;
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}
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ExprBlock bPop = m_stack.top();
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if (bPop.op == TOKEN_lparen)
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{
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m_stack.pop();
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break;
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}
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hr = m_eblocks.Add(bPop);
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if (FAILED(hr))
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return hr;
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m_stack.pop();
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}
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continue;
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}
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else if (b.op != TOKEN_lparen)
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{
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// Pop all operators of lower precedence off the stack. (This won't pass a left paren because its precedence is set to 0.)
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// Exception: don't pop a unary operator if the new one is also unary.
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int iNewPrecidence = Precedence(b.op);
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bool fNewUnary = b.op == TOKEN_sub || b.op == TOKEN_op_not;
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while (!m_stack.empty()) // note that there's a break inside the loop as well
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{
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ExprBlock bPop = m_stack.top();
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if (Precedence(bPop.op) < iNewPrecidence)
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break;
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if (fNewUnary && (bPop.op == TOKEN_sub || bPop.op == TOKEN_op_not))
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break;
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hr = m_eblocks.Add(bPop);
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if (FAILED(hr))
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return hr;
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m_stack.pop();
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}
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}
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// now push the new operator onto the stack
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hr = m_stack.push(b);
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if (FAILED(hr))
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return hr;
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}
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}
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while (!m_stack.empty())
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{
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ExprBlock bPop = m_stack.top();
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if (bPop.op == TOKEN_lparen)
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{
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assert(false);
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return E_FAIL;
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}
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hr = m_eblocks.Add(bPop);
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if (FAILED(hr))
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return hr;
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m_stack.pop();
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}
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// Add the teminating (_end) block
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hr = m_eblocks.Add(ExprBlock(ExprBlock::cons_end()));
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if (FAILED(hr))
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return hr;
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return S_OK;
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}
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