159 lines
4.8 KiB
NASM
159 lines
4.8 KiB
NASM
|
title ulldiv - unsigned long divide routine
|
||
|
;***
|
||
|
;ulldiv.asm - unsigned long divide routine
|
||
|
;
|
||
|
; Copyright (c) 1985-1994, Microsoft Corporation. All rights reserved.
|
||
|
;
|
||
|
;Purpose:
|
||
|
; defines the unsigned long divide routine
|
||
|
; __aulldiv
|
||
|
;
|
||
|
;*******************************************************************************
|
||
|
|
||
|
|
||
|
.xlist
|
||
|
include cruntime.inc
|
||
|
include mm.inc
|
||
|
.list
|
||
|
|
||
|
;***
|
||
|
;ulldiv - unsigned long divide
|
||
|
;
|
||
|
;Purpose:
|
||
|
; Does a unsigned long divide of the arguments. Arguments are
|
||
|
; not changed.
|
||
|
;
|
||
|
;Entry:
|
||
|
; Arguments are passed on the stack:
|
||
|
; 1st pushed: divisor (QWORD)
|
||
|
; 2nd pushed: dividend (QWORD)
|
||
|
;
|
||
|
;Exit:
|
||
|
; EDX:EAX contains the quotient (dividend/divisor)
|
||
|
; NOTE: this routine removes the parameters from the stack.
|
||
|
;
|
||
|
;Uses:
|
||
|
; ECX
|
||
|
;
|
||
|
;Exceptions:
|
||
|
;
|
||
|
;*******************************************************************************
|
||
|
|
||
|
CODESEG
|
||
|
|
||
|
_aulldiv PROC NEAR
|
||
|
|
||
|
push ebx
|
||
|
push esi
|
||
|
|
||
|
; Set up the local stack and save the index registers. When this is done
|
||
|
; the stack frame will look as follows (assuming that the expression a/b will
|
||
|
; generate a call to uldiv(a, b)):
|
||
|
;
|
||
|
; -----------------
|
||
|
; | |
|
||
|
; |---------------|
|
||
|
; | |
|
||
|
; |--divisor (b)--|
|
||
|
; | |
|
||
|
; |---------------|
|
||
|
; | |
|
||
|
; |--dividend (a)-|
|
||
|
; | |
|
||
|
; |---------------|
|
||
|
; | return addr** |
|
||
|
; |---------------|
|
||
|
; | EBX |
|
||
|
; |---------------|
|
||
|
; ESP---->| ESI |
|
||
|
; -----------------
|
||
|
;
|
||
|
|
||
|
DVND equ [esp + 12] ; stack address of dividend (a)
|
||
|
DVSR equ [esp + 20] ; stack address of divisor (b)
|
||
|
|
||
|
;
|
||
|
; Now do the divide. First look to see if the divisor is less than 4194304K.
|
||
|
; If so, then we can use a simple algorithm with word divides, otherwise
|
||
|
; things get a little more complex.
|
||
|
;
|
||
|
|
||
|
mov eax,HIWORD(DVSR) ; check to see if divisor < 4194304K
|
||
|
or eax,eax
|
||
|
jnz short L1 ; nope, gotta do this the hard way
|
||
|
mov ecx,LOWORD(DVSR) ; load divisor
|
||
|
mov eax,HIWORD(DVND) ; load high word of dividend
|
||
|
xor edx,edx
|
||
|
div ecx ; get high order bits of quotient
|
||
|
mov ebx,eax ; save high bits of quotient
|
||
|
mov eax,LOWORD(DVND) ; edx:eax <- remainder:lo word of dividend
|
||
|
div ecx ; get low order bits of quotient
|
||
|
mov edx,ebx ; edx:eax <- quotient hi:quotient lo
|
||
|
jmp short L2 ; restore stack and return
|
||
|
|
||
|
;
|
||
|
; Here we do it the hard way. Remember, eax contains DVSRHI
|
||
|
;
|
||
|
|
||
|
L1:
|
||
|
mov ecx,eax ; ecx:ebx <- divisor
|
||
|
mov ebx,LOWORD(DVSR)
|
||
|
mov edx,HIWORD(DVND) ; edx:eax <- dividend
|
||
|
mov eax,LOWORD(DVND)
|
||
|
L3:
|
||
|
shr ecx,1 ; shift divisor right one bit; hi bit <- 0
|
||
|
rcr ebx,1
|
||
|
shr edx,1 ; shift dividend right one bit; hi bit <- 0
|
||
|
rcr eax,1
|
||
|
or ecx,ecx
|
||
|
jnz short L3 ; loop until divisor < 4194304K
|
||
|
div ebx ; now divide, ignore remainder
|
||
|
mov esi,eax ; save quotient
|
||
|
|
||
|
;
|
||
|
; We may be off by one, so to check, we will multiply the quotient
|
||
|
; by the divisor and check the result against the orignal dividend
|
||
|
; Note that we must also check for overflow, which can occur if the
|
||
|
; dividend is close to 2**64 and the quotient is off by 1.
|
||
|
;
|
||
|
|
||
|
mul dword ptr HIWORD(DVSR) ; QUOT * HIWORD(DVSR)
|
||
|
mov ecx,eax
|
||
|
mov eax,LOWORD(DVSR)
|
||
|
mul esi ; QUOT * LOWORD(DVSR)
|
||
|
add edx,ecx ; EDX:EAX = QUOT * DVSR
|
||
|
jc short L4 ; carry means Quotient is off by 1
|
||
|
|
||
|
;
|
||
|
; do long compare here between original dividend and the result of the
|
||
|
; multiply in edx:eax. If original is larger or equal, we are ok, otherwise
|
||
|
; subtract one (1) from the quotient.
|
||
|
;
|
||
|
|
||
|
cmp edx,HIWORD(DVND) ; compare hi words of result and original
|
||
|
ja short L4 ; if result > original, do subtract
|
||
|
jb short L5 ; if result < original, we are ok
|
||
|
cmp eax,LOWORD(DVND) ; hi words are equal, compare lo words
|
||
|
jbe short L5 ; if less or equal we are ok, else subtract
|
||
|
L4:
|
||
|
dec esi ; subtract 1 from quotient
|
||
|
L5:
|
||
|
xor edx,edx ; edx:eax <- quotient
|
||
|
mov eax,esi
|
||
|
|
||
|
;
|
||
|
; Just the cleanup left to do. edx:eax contains the quotient.
|
||
|
; Restore the saved registers and return.
|
||
|
;
|
||
|
|
||
|
L2:
|
||
|
|
||
|
pop esi
|
||
|
pop ebx
|
||
|
|
||
|
ret 16
|
||
|
|
||
|
_aulldiv ENDP
|
||
|
|
||
|
end
|